Thực hiện phép tính:
a) (15,25 + 3,75).4 + (20,71 + 5,29).5;
b) \[\frac{4}{{20}} + \frac{{16}}{{42}} + \frac{6}{{15}} + \frac{{ - 3}}{5} + \frac{2}{{21}} + \frac{{ - 10}}{{21}} + \frac{3}{{20}}\];
c) \[\frac{5}{{11}}.\frac{5}{7} + \frac{5}{{11}}.\frac{2}{7} + \frac{6}{{11}};\]
d) \(\left( { - \frac{5}{{24}} + 0,75 + \frac{7}{{12}}} \right):\left( { - 2\frac{1}{8}} \right)\).
Hướng dẫn giải:
a) (15,25 + 3,75).4 + (20,71 + 5,29).5
= 19.4 + 26.5
= 76 + 130
= 206
b) \[\frac{4}{{20}} + \frac{{16}}{{42}} + \frac{6}{{15}} + \frac{{ - 3}}{5} + \frac{2}{{21}} + \frac{{ - 10}}{{21}} + \frac{3}{{20}}\]
\[ = \frac{1}{5} + \frac{8}{{21}} + \frac{2}{5} + \frac{{ - 3}}{5} + \frac{2}{{21}} + \frac{{ - 10}}{{21}} + \frac{3}{{20}}\]
\[ = \frac{1}{5} + \frac{2}{5} + \frac{{ - 3}}{5} + \frac{8}{{21}} + \frac{2}{{21}} + \frac{{ - 10}}{{21}} + \frac{3}{{20}}\]
\[ = \left( {\frac{1}{5} + \frac{2}{5} + \frac{{ - 3}}{5}} \right) + \left( {\frac{8}{{21}} + \frac{2}{{21}} + \frac{{ - 10}}{{21}}} \right) + \frac{3}{{20}}\]
\[ = \frac{{1 + 2 + \left( { - 3} \right)}}{5} + \frac{{8 + 2 + \left( { - 10} \right)}}{{21}} + \frac{3}{{20}}\]
\( = \frac{0}{5} + \frac{0}{{21}} + \frac{3}{{20}}\)
\( = 0 + 0 + \frac{3}{{20}}\)
\[ = \frac{3}{{20}}\]
c) \[\frac{5}{{11}}.\frac{5}{7} + \frac{5}{{11}}.\frac{2}{7} + \frac{6}{{11}}\]
\[ = \left( {\frac{5}{{11}}.\frac{5}{7} + \frac{5}{{11}}.\frac{2}{7}} \right) + \frac{6}{{11}}\]
\[ = \frac{5}{{11}}.\left( {\frac{5}{7} + \frac{2}{7}} \right) + \frac{6}{{11}}\]
\( = \frac{5}{{11}}.\frac{7}{7} + \frac{6}{{11}}\)
\( = \frac{5}{{11}}.1 + \frac{6}{{11}}\)
\[ = \frac{5}{{11}} + \frac{6}{{11}}\]
\( = \frac{{5 + 6}}{{11}}\)
\( = \frac{{11}}{{11}}\)
= 1.
d) \(\left( { - \frac{5}{{24}} + 0,75 + \frac{7}{{12}}} \right):\left( { - 2\frac{1}{8}} \right)\)
\( = \left( { - \frac{5}{{24}} + \frac{3}{4} + \frac{7}{{12}}} \right):\left( { - \frac{{17}}{8}} \right)\)
\( = \left( { - \frac{5}{{24}} + \frac{{18}}{{24}} + \frac{{14}}{{24}}} \right):\left( { - \frac{{17}}{8}} \right)\)
\( = \frac{{ - 5 + 18 + 14}}{{24}}:\left( { - \frac{{17}}{8}} \right)\)
\( = \frac{9}{8}.\left( { - \frac{8}{{17}}} \right)\)
\[ = \frac{{9.\left( { - 8} \right)}}{{8.17}}\]
\[ = - \frac{9}{{17}}\]
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